Can you do it perfectly?

Too many odd number vertices theres no path

It’s not possible. Euler showed that you have to start and then end at an odd-number intersection so it can only be achieved for shapes with no more than 2 such points. This shape has 4 such points so it cannot be done.

This is an impossible game because the number of odd points is not two.

Spread your legs and at the same time and walk two path in the middle

Can't be done. More than two nodes with three paths.

I could tell ya how but then I’d have to kill you

Hey @grok c’est quoi la solution ?

Blocking you because you are sharing impossible task.

Start at upper right make the number 5 then the last diagonal line

I have never seen anyone do this correctly

Correction to my previous post : - - because the number of odd-points (=4) is neither 0 or 2.

@grok show me the answer

Hey @grok, zeig mir die Lösungen

It's not possible

Depends on the rules, it is possible if you walk on all 4s.

This looks impossible. I’m I right @grok

Correct Answer video show me @grok

Do you have to keep two feet on the same line?

Mathematically impossible

It's impossible. 3 nodes with an odd number of edges.

No way

@grok what's the way around

Not possible at all

씨박 할수도없는걸 그려놓고 뿅망치든년 매우 패라

No

@Grok Solve This Puzzle

@grok mostre qual seria o caminho correto ?

the way she just commits to the diagonal like its nothing is the whole vibe honestly

If one of the lines can be crossed twice this would've been possible.

Muzukashī

Impossible

its impossible

@grok do it correct