Loading video...
Video Failed to Load
Cool and simple proof: Are there two irrationals a & b such that a^b is rational? Consider √2^√2. If it's rational, we're done. If it's irrational then √2^√2^√2=√2^2=2 is rational, we're done. This is a non-constructive existence proof!
20,249 views • 4 months ago •via X (Twitter)
0 Comments
No comments available
Comments from the original post will appear here
