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For dynamically linked GCC/glibc programs on Linux, main() is not the process entry point. The kernel starts the loader. It maps libc and applies relocations. _start passes main to glibc, which initializes the process and calls it. I traced the path from source.c to main().

16,714 görüntüleme • 12 gün önce •via X (Twitter)

10 Yorum

why profil fotoğrafı
why12 gün önce

The jump from the kernel entry point to _start, then through libc before main(), is one of those details that makes the runtime feel much less magical.

Recandle profil fotoğrafı
Recandle12 gün önce

Most people think a C program starts at main(). It doesn’t. The kernel starts the loader first.

Sharapov Andrei profil fotoğrafı
Sharapov Andrei10 gün önce

Almost. The kernel does not start _start. It maps the ELF, reads PT_INTERP, jumps into Relocations finish there. Only then does control reach _start, which passes &main into _libc_start_main. main is a callback. If your mental model starts at main, you already skipped the ABI.

klöss profil fotoğrafı
klöss12 gün önce

insightful

ItsekiriBro.skr profil fotoğrafı
ItsekiriBro.skr12 gün önce

@tweem 110000 views

Ivo.usduc 💹🧲 profil fotoğrafı
Ivo.usduc 💹🧲12 gün önce

Never fade Tetsuo

GuessNope profil fotoğrafı
GuessNope6 gün önce

It's not the entry point for statically linked ones either. It's just the start of the C platform.

Nidhi Singhal profil fotoğrafı
Nidhi Singhal12 gün önce

@VOLDEMORT2X 😭👈🏻

schrodinger's catgirl profil fotoğrafı
schrodinger's catgirl11 gün önce

cool

Lee Revell profil fotoğrafı
Lee Revell11 gün önce

I tied for the biggest bug bounty at my last employer with an LD_PRELOAD exploit. Any support tech could have gotten root

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