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No one plays [Devils Never Cry] better than [One-Man Show] 🔴Post goal: 150 retweets 🎁Reward: 5 Random Hunters get a $10 gift card each 🌎Pre-register: #DevilMayCryPeakofCombat #Capcom #DevilMayCry #RockTheBloodyHunt

374,309 Aufrufe • vor 2 Jahren •via X (Twitter)

9 Kommentare

Profilbild von Devil May Cry: Peak Of Combat
Devil May Cry: Peak Of Combatvor 2 Jahren

Congratulations winners! @nexamusfortress @revvy_afterlife @hopeis_my @Lonewol64 @TheDaikuri Thank you for participating in the event! Please check your DMs to see the reward!

Profilbild von Nikkisparda
Nikkispardavor 2 Jahren

Ya quiero jugarlo oooo T u T

Profilbild von Mister_P
Mister_Pvor 2 Jahren

@JerichoFive

Profilbild von leo
leovor 2 Jahren

🥱

Profilbild von Leave3D 🌌 / 残す3だ (also on other app)
Leave3D 🌌 / 残す3だ (also on other app)vor 2 Jahren

"But you are never become a man"

Profilbild von Rykard
Rykardvor 2 Jahren

that's a shit reward. Give me 10 s rank weapons

Profilbild von Rahul Vaghela
Rahul Vaghelavor 2 Jahren

When it will be available in India?

Profilbild von ANDROOSGAMEPLAY
ANDROOSGAMEPLAYvor 2 Jahren

I'm still getting an error with the gift card I won😂

Profilbild von Andres
Andresvor 2 Jahren

Yo quiero mi regalo de hunters y la gift de 10 por favor yo vengo aportando críticas constructivas y chequeando las fallas y optimización del juego para después decirles a ustedes que deben mejorar soy participante de las betas anteriores deseo ganar

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Discrete Fourier Transform by hand ✍️ ~ 12 steps walkthrough below Here is a little-known secret about the DFT and the inverse DFT: it is just matrix multiplication in both directions, one the transpose of the other, exactly like the forward pass and backpropagation I drew in other examples. Goal: recover which cosine waves a signal is made of, using nothing but multiplication and addition. = 1. Given = Three signals written as sums of cosines, and a fourth, X, that we do not know yet. = 2. Frequency matrix F = Let us write the coefficients as a matrix. Each signal is a row, each frequency a column, so A = cos(w) + 2cos(2w) becomes [1, 2, 0, 0]. = 3. Sample the waves = We read the four cosine waves at ten discrete time points. That word "discrete" is the whole difference between this and the continuous transform. = 4. Cosine matrix W = Let us write those samples as a matrix: each frequency a row, each time point a column. = 5. Frequency to time = We multiply F by W. That combines the four cosine waves in the proportions F specifies, and the result T is the three signals as they would look in time. = 6. Transpose = Let us stand each signal up as a column. = 7. Time to frequency = We multiply W by that transpose. Every cell is the dot product of one signal with one cosine wave, which measures how much of that wave the signal contains. Zero means none of it. = 8. Scale = Let us multiply by 2/n, with n = 10. The projections come out five times too large, and this is the correction. = 9. Transpose back = We turn it back around, and it is F again, exactly. That is the check: the transform recovered the coefficients we started from. = 10. Now solve for X = Let us run the same multiplication on the one signal whose recipe we never knew. = 11. Scale = We divide by 5 again. = 12. Transpose back = And X reads [0, 0, 3, 2], which says X = 3cos(3w) + 2cos(4w). Note: I originally drew this to show that the DFT is a special case of a convolution layer, its filters fixed to sine and cosine waves rather than learned. No wonder, then, that a convolution layer free to learn its own filters can be trained to process signals. 💾 Save this post!

Tom Yeh

25,684 Aufrufe • vor 1 Monat

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