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They do not know how to solve this problem. You can?

35,511,007 次观看 • 1 年前 •via X (Twitter)

38 条评论

FinalBrandon 的头像
FinalBrandon1 年前

Just go around the world. Easy

Mark Dania 的头像
Mark Dania1 年前

Solved it!

💪🎭..Rai ji..💪🎭 的头像
💪🎭..Rai ji..💪🎭1 年前

Can you solve this puzzle?

Global Index 的头像
Global Index1 年前

Carving a piece of art out of watermelon.

Damon Strong 的头像
Damon Strong1 年前

Start in the upper right corner.

The Night Warrior 的头像
The Night Warrior1 年前

Hard puzzle to solve from the 18th century

José Crespo-Barrios, PhD 的头像
José Crespo-Barrios, PhD1 年前

Of course you can. It is just a matter of ...perspective

The Night Warrior 的头像
The Night Warrior1 年前

The puzzle that seems difficult to solve.

Global Index 的头像
Global Index1 年前

Collective intelligence of ants solving a puzzle

Ajakara🐸_🙂‍↔️ 的头像
Ajakara🐸_🙂‍↔️1 年前

Simplest way

Niyi ❖,❖ 的头像
Niyi ❖,❖1 年前

Not solvable

Phil777 的头像
Phil7771 年前

Easy

Viral vortex 的头像
Viral vortex1 年前

This video makes me happy

Atlanteum 的头像
Atlanteum1 年前

It can be done, but it requires the contestant to slip into non-Euclidean dimensions of angular space, which will, of course, make them visible to the hounds of Tindalos... and, well... it's just not worth it at that point -

💪🎭..Rai ji..💪🎭 的头像
💪🎭..Rai ji..💪🎭1 年前

Lots of people get it wrong answer. Can you solve it?

Milly🎲 的头像
Milly🎲1 年前

If you cant retrace your steps or go diagonally its impossible

たかぴ@梟麗心愚🦉 的头像
たかぴ@梟麗心愚🦉1 年前

Very easy

ACΞ ♠ 的头像
ACΞ ♠1 年前

@grok how fast can you solve this?

Grok 的头像
Grok1 年前

@TheFigen_ Instantly—it's impossible. The yellow tape forms a graph with more than two odd-degree vertices, so there's no Eulerian path to trace all lines without lifting your foot or retracing. That's why they keep failing.

Intellectual_ 的头像
Intellectual_1 年前

@charlesace_ @TheFigen_ They are looking for Hamiltonian paths not Eulerian paths

Grok 的头像
Grok1 年前

@charlesace_ @TheFigen_ The task in the video is to trace all the tape lines (edges) without lifting or retracing, which is an Eulerian path problem. It's impossible due to multiple odd-degree vertices. Hamiltonian paths focus on visiting vertices once, but here it's about covering edges.

Intellectual_ 的头像
Intellectual_1 年前

@charlesace_ @TheFigen_ No, the task is to find a path that traverse each yellow tape box (vertices) exactly once

Grok 的头像
Grok1 年前

Upon reviewing the video, the participants are attempting to trace all the yellow tape lines continuously without retracing or lifting their path, which aligns with an Eulerian path problem. The graph has four odd-degree vertices, making it impossible. If the goal was visiting each box once (Hamiltonian), a path exists in a 3x3 grid, but that's not what the attempts show.

Intellectual_ 的头像
Intellectual_1 年前

@charlesace_ @TheFigen_ It has nothing to do with tape lines individually, the lines for different boxes, and those boxes are vertices. Nobody cares about which line u step over

Grok 的头像
Grok1 年前

The video shows participants trying to trace all yellow tape lines (edges) continuously without retracing or lifting, an Eulerian path problem. With 8 odd-degree vertices in the 4x4 grid graph, it's impossible. The green overlay follows the lines, not box centers, confirming this. If it were visiting boxes (Hamiltonian), it'd be possible, but that's not what's depicted.

Becca 的头像
Becca1 年前

here's the solution:

💪🎭..Rai ji..💪🎭 的头像
💪🎭..Rai ji..💪🎭1 年前

Could you solve this?

J. K1NG | 44/8LP 🐉♏️🇵🇷🇨🇴 的头像
J. K1NG | 44/8LP 🐉♏️🇵🇷🇨🇴1 年前

lol

بنت الهيلا 💎 的头像
بنت الهيلا 💎1 年前

🤭🤭🤭🤭🤭🤭🤭🤭

Galileo 的头像
Galileo1 年前

ez

🇮🇳Rohit🇮🇳 的头像
🇮🇳Rohit🇮🇳1 年前

Here we go ☺️😎

Sigma Vibe 的头像
Sigma Vibe1 年前

A puzzle that seems hard to solve.

BAT!FE 的头像
BAT!FE1 年前

Hardest puzzle ever

Zero-G Templar 的头像
Zero-G Templar1 年前

if moving on a diaganal is permited then their are numberious paths!

Aruvin 💊 的头像
Aruvin 💊1 年前

This is solvable if you allow them to walk out of the boxes or walk diagonally.

Observer 的头像
Observer1 年前

I seriously do not understand the point of this exercise

Melon Musk 的头像
Melon Musk1 年前

Simple!

Aaron 的头像
Aaron1 年前

You can prove it's impossible by giving the squares alternating colors. There's 8 white squares and 6 black squares, but any path that visits 6 black squares must visit 5, 6, or 7 white squares, depending on starting/ending colors.

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